K=wv2 divided by 2g for w

asked Feb 22, 2015 225k views

1 vote

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3 votes

$K=(wv^2)/(2g)\ \ \ \ \ \ |\cdot2g\\\\2Kg=wv^2\ \ \ \ \ |:v^2\\\\\boxed{w=(2Kg)/(v^2)}$

Mintgreen answered Feb 25, 2015

7.0k points

4 votes

$K=(wv^2)/(2g)\ \ \ \ \ |multiply\ both\ sides\ by\ 2g\\\\2gK=wv^2\ \ \ \ \ |divide\ both\ sides\ by\ v^2\\\\\boxed{w=(2gK)/(v^2)}$

Shaunlim answered Feb 27, 2015

7.2k points

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