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A 75.0g sample of liquid contains 17.5% by mass of H3PO4 (molar mass = 98.0g/mol). If
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A 75.0g sample of liquid contains 17.5% by mass of H3PO4 (molar mass = 98.0g/mol). If

User Nyc
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assuming no other acid is in the H3PO4 mix, then
a) the equation
2H3PO4 + 3Ba(OH)2>>3H2O+Ba3(PO3)2

titration equation:
nb*Ma*Va=na*Mb*Vb
nb*molesacid=na*molesbase
3*75*.175/98=2*Molaritybase*.215
0.927 mol/L
User Gosi
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