243,353 views
28 votes
28 votes
Which of the following shows the simplified form of (sin x)/(1 - cos x)? 1sin x + tan xsin x + cot xcsc x + cot x

User Alexkovelsky
by
3.1k points

1 Answer

11 votes
11 votes

We want to simplify the following expression


(\sin x)/(1-\cos x)

We can start by multiplying both numerator and denominator by the conjugate of the denominator:


\begin{gathered} (\sin(x))/(1-\cos(x))=(\sin(x))/(1-\cos(x))\cdot(1+\cos(x))/(1+\cos(x)) \\ \\ =(\sin(x)(1+\cos(x)))/((1-\cos(x))(1+\cos(x))) \\ \\ =(\sin(x)\cdot(1)+\sin(x)\cdot\cos(x))/((1)\cdot(1)+(1)\cdot(\cos(x))+(-\cos(x))\cdot(1)+(-\cos(x))\cdot(\cos(x))) \\ \\ \begin{equation*} =(\sin(x)+\sin(x)\cos(x))/(1-\cos^2(x)) \end{equation*} \end{gathered}

Then, using the identity


\sin^2x+\cos^2x=1\implies\sin^2x=1-\cos^2x

We can rewrite our expression as


(\sin(x)+\sin(x)\cos(x))/(1-\cos^2(x))=(\sin(x)+\sin(x)\cos(x))/(\sin^2(x))=(1)/(\sin x)+(\cos x)/(\sin x)

By definition of cosecant and cotangent, our expression can be written as


(1)/(\sin x)+(\cos x)/(\sin x)=\csc x+\cot x

and this is our answer.


(\sin x)/(1-\cos x)=\csc x+\cot x

User Remi Guan
by
2.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.