Question

(05.02)A doghouse is to be built in the shape of a right trapezoid, as shown below. What is the area of the doghouse?

A right trapezoid with top side 7 feet and height 7 feet. The bottom side is extended to the right with 3 more feet.
24.5 square feet
59.5 square feet
70 square feet
147 square feet

Answer 1

the area of the trapezoid is 70sq ft

Answer 2

The area of the doghouse is
`59.5\ ft^(2)`

Explanation:

we know that

The area of trapezoid is equal to

`A=(1)/(2)(b1+b2)h`

where

b1,b2 are the parallel bases of trapezoid

h is the height of trapezoid

in this problem we have

`b1=7\ ft`

`b2=7+3=10\ ft`

`h=7\ ft`

substitute

`A=(1)/(2)(7+10)7=59.5\ ft^(2)`