How many grams of potassium iodide, KI, are required to make 2.0 L of a 0.1M solution

asked Oct 6, 2017 190k views

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1 vote

Volume = 2.0 L

Molarity = 0.1 M

Molar mass KI = 166.0028 g/mol

mass = V x M x molar mass

mass = 2.0 x 0.1 x 166.0028

= 33.20056 g of KI

FlogFR answered Oct 12, 2017

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