Question

In a dihybrid cross for round and yellow seeds (RrYy x RrYy), what is the probability of having green and wrinkled seeds?

Answer 1

The probability of having green and wrinkled seeds is equal to
`6.25`%

Step-by-step explanation:

Here R allele is dominant over r allele and Y allele is dominant over y allele.

Thus, a green phenotype will have genotype rr

and a wrinkled phenotype will have genotype yy

The punnet square representing the cross between RrYy and RrYy is as follows -

RY Ry rY ry

RY RRYY RRYy RrYY RrYy

Ry RRYy RRyy RrYy Rryy

rY RrYY RrYy rrYY rrYy

ry RrYy Rryy rrYy rryy

Out of all 16 offspring, only one offspring with genotype "rryy" represents green and wrinkled seeds.

Thus, the probability of having green and wrinkled seeds is equal to

`(1)/(16) * 100\\= 6.25`%

Answer 2

Probability of green and wrinkled seeds is
`(1)/(16)`

Step-by-step explanation:

Here ,

"R" represents the allele for round seeds

and "r" represents the allele for wrinkled seeds

"Y" represents the allele for yellow seeds and

"y " represents the allele for green seeds

Thus,

Dihybrid cross for round and yellow seeds (RrYy) means that the round allele is dominant overwrinkled seeds and yellow is dominant over green color seed

RrYy * RrYy

RY Ry rY ry

RY RRYY RRYy RrYY RrYy

Ry RRYy RRyy RrYy Rryy

rY RrYY RrYy rrYY rrYy

ry RrYy Rryy rrYy rryy

Round & Yellow seeds- RRYY, RRYy, RrYY, RrYY, RRYy, RrYy, RrYY, RrYy, RrYy

Round & Green seeds – RRyy, Rryy, Rryy

Wrinkled & Yellow Seeds – rrYY, rrYy, rrYY

Wrinkled &green seeds - rryy

Number of green and wrinkled seeds - 1

Probability of green and wrinkled seeds is
`(1)/(16)`