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7 votes
7 votes
How do you solve 4√-6 x 2√-3?

User Kamarey
by
2.1k points

1 Answer

7 votes
7 votes

4\sqrt[]{-6}*2\sqrt[]{-3}=(4*2)(\sqrt[]{-6})(\sqrt[]{-3})=8\sqrt[]{-6}\sqrt[]{-3}
=8(\sqrt[]{(-1)(6)})(\sqrt[]{(-1)(3)})=8(i\sqrt[]{6})(i\sqrt[]{3})
=8i^2(\sqrt[]{6})(\sqrt[]{3})=-8(\sqrt[]{(3)(2)})(\sqrt[]{3})=-8(\sqrt[]{3}^2)(\sqrt[]{2})=-24\sqrt[]{2}

then the answer will be -24√2

User Cristian Todea
by
3.0k points
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