Question

I need help on finding point slope form for the slope of 6 and passing through (-7,1)

Answer 1

To answer this question, we need to use the following equation (point-slope):

`y-y1=m(x-x1)`

We have:

• m = 6

,

• The point is (-7, 1)

Then

`y-1=6(x-(-7))\Rightarrow y-1=6(x+7)\Rightarrow y-1=6x+42_{}`

Therefore

`y=6x+42+1\Rightarrow y=6x+43`

Then the point-slope form of a line with m = 6, passing through (-7,1) is

`y-1=6(x+7)`

`y=6x+43`

And the previous result is the standard form of the equation.