Question

Which is the acceleration of a 32-kg object if a 6.75-N force is applied to it?

A 216.00 m/s2
B.21.09 m/s2
C. 4.74 m/s2
D. 0.21 m/s2

Answer 1

F=ma F/m=a 6.75/32=0.21m/s2 means d is your right answer!

Answer 2

Аnswer is: the acceleration is D. 0.21 m/s².

Newton's second law of motion: F = m · a.

F - force applied.

m - mass of the object receiving the force.

a - the acceleration of the object.

a = F ÷ m.

a = 6.75 N ÷ 32 kg.

a = 0.21 m/s².

One newton is the force needed to accelerate one kilogram of mass at the rate of one metre per second squared in direction of the applied force.