Question

According to Boyle's law, the relation = p1. V2 ——=— P2 V1holds for pressures p1 and p2 and volumes V1, and V2 of a gas at constant temperature. Find V1, if p₁ = 36.5 kPa,P2=84.1 kpa, and v2=.0447 m^3(Simplify your answer. Type an integer or decimal rounded to four decimal places as needed.)

Answer 1

From the formula given we have that

`\begin{gathered} (P_1)/(P_2)=(V_2)/(V_1) \\ Now\text{ substitute } \\ P_1=36.5,P_2=84.1,V_2=0.0447\text{ into the equation, we have } \end{gathered}`

V1 as

`\begin{gathered} (36.5)/(84.1)=(0.0447)/(V_1) \\ cross\text{ multiplying we have } \\ 36.5V_1=0.0447*84.1 \\ V_1=(0.0447*84.1)/(36.5) \\ V_1=0.1029937 \end{gathered}`

Hence the answer is

`V_1=0.1030\text{ }m^3`