Question

3Cu(s) + 8HNO3(aq) → 3Cu(NO3)2(s) + 2NO(g) + 4H2O(l)

Calculate the number of moles of water produced when 3.3 mol of Cu(NO3)2 are formed in the reaction
A. 6.6 mol
B. 8.8 mol
C. 4.4 mol
D. 4.9 mol

Answer 1

Mole ratio:

3 Cu(s) + 8 HNO₃(aq) = 3 Cu(NO₃)₂(s) + 2 NO(g) + 4 H₂O(l)

3 moles Cu(NO₃)₂ ----------------- 4 moles H₂O
3.3 moles Cu(NO₃)₂ ---------------- ??

moles H₂O = 3.3 x 4 / 3

moles H₂O = 13.2 / 3

=> 4.4 moles of H₂O

Answer C