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A 3.6-kg chihuahua charges at a speed of 3.3m/s. what is the magnitude of the average force needed to bring the chihuahua to a stop in 0.50s?

A 3.6-kg chihuahua charges at a speed of 3.3m/s. what is the magnitude of the average force needed to bring the chihuahua to a stop in 0.50s?
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A 3.6-kg chihuahua charges at a speed of 3.3m/s. what is the magnitude of the average force needed to bring the chihuahua to a stop in 0.50s?

User Shilch
by
8.4k points

1 Answer

3 votes
...
use this equation
F delta(t) = m delta(v)
F (0.50) = 3.6 (3.3)
F = 23.8 N
User Kaletha
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8.4k points
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