Question

What is the point slope form of the line with slope −14 that passes through the point (−2, 9) ? y−2=−14(x 9) y 9=−14(x−2) y 2=−14(x−9) y−9=−14(x 2)

Answer 1

I hope this helps you



slope = -14

x'= -2

y'=9

slope. (x'-x)=y'-y


-14. (-2-x)=9-y


-14. -2 -14. (-x)=9-y


28+14x=9-y


y-9= -14x-28


y-9=-14 (x+2)

Answer 2

y-9 = -14(x+2)

Explanation:

The formula for finding the equation of a line is y = mx+c or y-y1= m(x-x1) where;

m is the slope or gradient = -14

c is the intercept

(x1,y1) is a point on the line given as (-2,9) i.e x1 = -2, y1 = 9

Substituting the value of the slope and the point (x1,y1) in the given equation of the line, the equation will become;

y-9 = -14(x-(-2))

y-9 = -14(x+2)