Question

According to recent UN figures, the annual gun homicide rate is 62.4 per one million residents in the US and 1.3 per one million residents in Britain. Compare the proportion of residents killed annually by guns using the (a) difference of proportions, (b) relative risk. Which measure is more useful for describing the strength of association

Answer 1

`P_D=61.1*10^(-4)`

`R_r=480`

Explanation:

From the question we are told that

Homicide rate in US
`R_U=62.4\ per\ one\ million`

Homicide rate in Britain
`R_B=1.3\ per\ one\ million`

Generally the equation for probability of homicide is mathematically given as

`P=(R)/(10^6)`

Generally the equation for probability of homicide in US is mathematically given as

`P_U=(62.4)/(10^6)`

`P_U=62.4*10^(-4)`

Generally the equation for probability of homicide in Britain is mathematically given as

`P_B=(1.3)/(10^6)`

`P_B=1.3*10^(-5)`

a)Generally the difference b/w the probabilities P_D is mathematically given as

`P_D=P_U-P_B`

`P_D=62.4*10^(-4)-1.3*10^(-5)`

`P_D=61.1*10^(-4)`

Therefore US annual homicide is
`P_D=61.1*10^(-4)` greater than Britain's

b)Generally the Relative risk is R_r is mathematically given as

`R_r=(P_U)/(P_B)`

`R_r=(62.4*10^(-4))/(1.3*10^(-5))`

`R_r=480`