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What is the perimeter of a rectangle whose width is (x-7) units and whose length is (3x-10 )

User Alexandre Fenyo
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1 Answer

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17 votes

The perimeter of a rectangle is given by:

P = 2l + 2w

where p is the perimeter of the rectangle

l is the length of the rectangle and w is the width of the rectangle

From the question length is given as: 3x-10 and the width is given to be x-7

substituting into the formula

P = 2l + 2w

P = 2(3x-10) + 2(x-7)

let's open the parenthesis and then simplifies

P = 6x - 20 + 2x - 14

P = 6x + 2x - 20 -14

P= 8x -34

Therefore the perimeter of the rectangle is equal to (8x- 34)

User Mickeymoon
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