Question

Solve x2 – 8x = 3 by completing the square. which is the solution set of the equation

Answer 1

I hope this helps you 1.x^2-8x-3=0 disctirminant =(-8)^2-4.1. (-3) disctirminant =64+12 disctirminant =76 x1,2= -b(+,-)square root of disctirminant /2a x1=-(-8)+square root of 76/2.1 x1=8+square root of 76/2 x2=8-square root of 76/2

Answer 2

`x-4=√(19)\Rightarrow x= 4+√(19)\\\\\ x-4=-√(19)\Rightarrow x= 4-√(19)`

is the solution set for the given equation

Explanation:

Given : Equation
`x^2-8x=3`

We have to find the solution set for the given equation using completing the square method.

Consider the given equation
`x^2-8x=3`

Write the given equation in form of
`x^2+2ax+a^2=\left(x+a\right)^2`

Comparing , we have,

x = x

2ax = -8x

a = - 4

Adding
`a^2=16` both side, we have,

`x^2-8x+\left(-4\right)^2=3+\left(-4\right)^2`

Simplify, we have,

`\left(x-4\right)^2=19`

`\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=√(a),\:-√(a)`

thus,

`(x-4)=\pm√(19)`

Therefore,

`x-4=√(19)\Rightarrow x= 4+√(19)\\\\\ x-4=-√(19)\Rightarrow x= 4-√(19)`

is the solution set for the given equation