Question

In the Netherlands there is an annual ice-skating race called the "Tours of the eleven towns" the total distance of the course is 2.00*10 squared km and the record time is 5 hours, 40 minutes, and 37 seconds. Calculate the average speed for the record time.

Answer 1

1hr=60mins 5hr=5 × 60=300+40=340mins 1min=3600secs 340Mins=3600×340=1224000secs/10mins 2000÷10=200km/mins

Answer 2

The average speed for the record time is 9.78 m/s.

Step-by-step explanation:

Given that,

Total distance
`d= 2.00*10^2\ km`

Time
`t= 5*60*60+40*60+37\ sec`

`t =20437\ sec`

We need to calculate the average speed for the record time

Using formula of the average speed

`v_(avg)=(D)/(T)`

Where, D = total distance

T = total time

Put the value into the formula

`v_(avg)=(2.00*10^2*10^(3))/(20437)`

`v_(avg)=9.78\ m/s`

Hence, The average speed for the record time is 9.78 m/s.