Question

A football field has a rectangular fenced area around it. It uses 40 feet of fencing material to enclose all four sides of the field. w Complete the table by giving the length and area for each width. width (feet) length (feet) area (square feet) 1 19 17 10 5 5 75

Answer 1

Given

40 feet of fencing

Equation

`\begin{gathered} P=2w+2l \\ A=wl \end{gathered}`

Table

w = 1 feet

l = 19 feet

A = 19 sq feet

w = 3 feet

l = 17 feet

A = 51 sq feet

w = 10 feet

l = 10 feet

A = 100 sq feet

w = 15 feet

l = 5 feet

A = 75 sq feet

Equation

x = width

A = w*l

l = A/w

40 = 2w + 2l

l = 20 - w

`-x^2+20x`