Required Answers :-
9.
Q:-If the perimeter of an isosceles triangle is 83 cm. and its base is 23 cm. Find the measure of its equal sides.
Answer:- As we know that Perimeter is the sum of all sides.
- Let the both side be x
- 83 = 23 + (x + x)
- 83 - 23 = 2x
- 60 = 2x
- 30 = x
Other two sides are 30 cm.
10.The perimeter of a rhombus is 5.6 cm. Find its side.
Answer:- As we know that
Side of Rhombus = Perimeter/4
- Side = 5.6/4
- Side = 1.4 cm
- Side is 1.4 cm
11.The perimeter of a rectangle is equal to that of a square with side 17 m. If the length of the
The perimeter of a rectangle is equal to that of a square with side 17 m. If the length of therectangle is 26 m. What is its breadth ?
Answer:- Perimeter of square = 4 × s
- Perimeter = 4 × 17
- Perimeter = 68 cm
Now,
- Perimeter of rectangle = 2(l + b)
- 68 = 2(26 + b)
- 68/2 = 26 + b
- 34 = 26 + b
- 34 - 26 = b
- 8 = b
- b=8
12.What is the cost of fencing a rectangular field of length 16 m and breadth 11 m at the rate of 12 per m.
Answer:- Perimeter = 2(l + b)
- Perimeter = 2(16 + 11)
- Perimeter = 2(27)
- Perimeter = 54 cm
Now,
- Total cost = 54 × 12
- Total cost = ₹648.
