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Solve 2(4x + 3) < 5x + 21.

User Skuntsel
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2 Answers

5 votes

Answer: x<5

Explanation:

User Myslik
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2 votes
First you simplyify both sides,

8x+6<5x+21

Then you subtract both sides,

8x+(6−5x)<5x+(21−5x)

3x+6<21

Subtract 6 from both sides,

3x+6−6<21−6

3x<15

finally you divide both sides by 3,


(3x)/(3) \ \textless \ (15)/(3)
Your answer is:x<5

Glad I could help. c:
User Meissnersd
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