Question

) A 1000-nF capacitor with circular parallel plates with a radius of 1cm is accumulating charge at the rate of 52 mC/s at some point in time. What will be the induced magnetic field strength if you are positioned 20 cm radially outward from the center of the plates

Answer 1

`B=5.2*10^-^8T`

Step-by-step explanation:

From the question we are told that

Capacitor
`c=1000nf`

Radius
`r=1cm =>0.001m`

Charge rate
`Q/t=52mC/s`

Distance
`d=20cm =0.2m`

Generally the rate of charge I is mathematically given as

`I=(dQ)/(dt)`

`I=52Cm/s`

`I=52*10^-^3C`

Generally the the magnetic field intensity at distance d is mathematically given as

`B=(\mu I)/(2\pi d)`

`B=((4 * \pi *10^-^7)(52*10^-^3C))/(2\pi (0.2))`

`B=5.2*10^-^8T`