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4. BE = 20, DE = 5, EO = 19 find DT(

4. BE = 20, DE = 5, EO = 19 find DT(-example-1
User Smentek
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1 Answer

11 votes
11 votes

For this exercise you need to remember the Intersecting chords theorem. This states that the product of the lengths of the segments of one chord is equal to the product of the lengths of the segments of the other chord.

In this case you can set up that:


BE\cdot EO=TE\cdot DE

You can identify that:


\begin{gathered} BE=20 \\ DE=5 \\ EO=19 \end{gathered}

Then, since you don't know the length TE, you can substitute these values into the equation and solve for TE:


\begin{gathered} BE\cdot EO=TE\cdot DE \\ (20)(19)=TE(5) \\ \\ (380)/(5)=TE \\ \\ TE=76 \end{gathered}

As you can observe, the length DT can be found by adding the length TE and the length DE. Then:


\begin{gathered} DT=TE+DE \\ DT=76+5 \\ DT=81 \end{gathered}

The answer is:


DT=81

User Jansanchez
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