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A shipment of marbles with a mean diameter of 27 mm and a standard deviation of 0.15 mm is normally distributed. By how many standard deviations does a marble with a diameter of 26.85 mm differ from the mean?

User Birante
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2 Answers

1 vote

Answer:

The answer would be 1

Explanation:

User Brad Harris
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1 vote

This could be solved by calculating the z-score. Its definition is the number of standard deviations from the mean a data point is. The formula is,

Z =║Data point – Mean║ / Std. dev.

Z = ║26.85 mm – 27 mm║ / 0.15

Z = 1

User Brokenbeatnik
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