Question

Rewrite the equation 2y^2+8y-2x+6=0 in standard form

A. (y+2)^2=2(x+1)
B. (y+4)^2=x+1
C. (y+2)^2=x+1
D. (y+2)^2=x-3

Answer 1

If you would like to rewrite the equation 2 * y^2 + 8 * y - 2 * x + 6 = 0 in the standard form, you can do this using the following steps:

2 * y^2 + 8 * y - 2 * x + 6 = 0 /2
y^2 + 4 * y - x + 3 = 0
(y + 2)^2 - 1 - x = 0
(y + 2)^2 = x + 1

The correct result would be C. (y+2)^2 = x + 1.