A 4kg bird has 8 joules of kinetic energy, how fast is it flying?

Question

asked Jan 16, 2017 86.8k views

2 Answers

Omarzouk · Answer 1 · 2017-01-22T02:27:58+0000

Answer:

The bird is flying at a velocity of
v=2(m)/(s)

Step-by-step explanation:

You should use the equation for the kinetic energy, that is:

K_(E)=(1)/(2)mv^(2)

where
K_(E) is the kinetic energy, m is the mass of the bird and v is its velocity.

Solving for v:

mv^(2)=2K_(E)

v^(2)=(2K_(E))/(m)

$v=\sqrt{(2K_(E))/(m)}$

And replacing the values given in the problem you have:

$v=\sqrt{(2*8J)/(4kg)}$

$v=\sqrt{(16J)/(4kg)}$

$v=\sqrt{4(m^(2))/(s^(2))}$

v=2(m)/(s)