Question

A bag of trail mix contains 36 peanuts, 21 almonds, 13 raisins, and 19 chocolate candies. Li hates raisins. If Li reaches into the bag and randomly selects one item, what is the probability that it will not be a raisin?

Answer 1

The probability that Li does not select a raisin is 76/89, obtained by subtracting the number of raisins from the total number of items and then dividing by the total number of items.

Step-by-step explanation:

• To find the probability that Li does not select a raisin from the bag, we first need to determine the total number of items in the bag.
• Adding up all the items: 36 peanuts + 21 almonds + 13 raisins + 19 chocolate candies gives us a total of 89 items.
• Since Li hates raisins, we subtract the number of raisins from the total number of items to find the number of items that are not raisins, which is 89 - 13 = 76.

Now, the probability that Li selects an item that is not a raisin is the number of items that are not raisins divided by the total number of items. Therefore, the probability is 76/89.

Answer 2

From the question, we can summarize that there are 76 non-raisins and 13 raisins. All in all, there are a total of 89 sweets in the bag.

There are 76 non-raisins because 36 peanuts + 21 almonds + 19 chocolate candies = 76.

To solve for the probability of picking a non-raisin sweet, we have the formula below:

`P=\frac{\text{total no. of non-raisin}}{\text{total no. of sweets in the bag}}`

Let's plug in the values that we have identified in the formula above.

`P=(76)/(89)=0.8539`

Therefore, the probability of not picking a raisin is 76/89 or 85.39%.