If f(5)=288.9 when r=0.05 for the function f(t)= pe^rt, then what is the approximate value of p?

Question

asked Jan 5, 2017 153k views

2 Answers

Ting · Answer 1 · 2017-01-11T05:21:45+0000

The general equation is: f(t)=
pe^(rt)

The given equation is: f(5)=288.9 when r = 0.05

Following the general equation, we know the following:

t=5, r = 0.05 and
pe^(rt) = 288.9

Substituting all unknowns, we can solve for p

pe^(0.05 * 5) = 288.9

Solving for p,

p = 225