Question

Rewrite the following equation in slope-intercept form,- 16x = + 2y - 5

Answer 1

Starting with the expression:

`-16x=2y-5`

Isolate y to write the expression in slope-intercept form:

`\begin{gathered} \Rightarrow5-16x=2y \\ \Rightarrow2y=5-16x \\ \Rightarrow y=(5)/(2)-8x \\ \Rightarrow y=-8x+(5)/(2) \end{gathered}`

Therefore, the slope-interept form of this equation, is:

`y=-8x+(5)/(2)`