a cylindrical paint roller has a length of 10 inches and a diameter of 1 1/2 inches. As the roller is dragged along a wall, if it completes 4 revolutions, what is the approximate area the roller will cover

asked Jun 14, 2017 82.3k views

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I hope this helps you radius= 1 1/2=1.2+1/2=3/2 lateral area= 2pi.r.height area= 2.pi.3/2.10 area =30pi 4.30pi=120pi

Murrekatt answered Jun 21, 2017

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