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Determine the sum of: −10y2+(−3y2)−4y2−(−6y2)

the 2 are squared

User Nitishagar
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1 Answer

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-10y^2 + (-3y^2) - 4y^2 - (-6y^2) =
-10y^2 - 3y^2 - 4y^2 + 6y^2 =
-17y^2 + 6y^2 =
- 11y^2
User Danny G
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