181k views
3 votes
Given the trinomial x^2-bx-c where both the first and the second signs are negative, the signs of the factors will be:

A. cannot determine
B. both negative
C. both positive
D. one positive and one negative

User DirtyBit
by
7.9k points

2 Answers

1 vote

Answer:

D

Explanation:

User Laurent T
by
6.9k points
5 votes

Answer: Option 'D' is correct.

Explanation:

Since we have given that


x^2-bx-c=0

Both the first and second signs are negative,

Let α and β are the roots of the
x^2-bx-c=0,

then, we know that the relationship between the zeroes and coefficients of quadratic equations:


\alpha+\beta =(-b)/(a)=b\\\\and\\\\\alpha \beta =(-c)/(a)=-c

Since the product of roots is positive.

So, the signs of the factors will be one positive and one negative.

Hence, Option 'D' is correct.

User Tgrez
by
6.6k points