Question

A magnetic field is normal to the plane of a 0.15 m x 0.30 m rectangular coil of 120 turns. The magnetic field is increased uniformly from 0.10 T to 1.5 T. Find the time interval for the change if an emf induced in the coil is 1.2 V.Group of answer choices0.23 s2.6 s6.3 s9.6 s

Answer 1

Given:

The number of turns in the coil is N = 120 turns

The emf induced in the coil is

`\epsilon\text{ = 1.2 V}`

The change in the magnetic field is

`\begin{gathered} \Delta B=\text{ 1.5-0.1} \\ =1.4\text{ T} \end{gathered}`

The area of the coil is

`\begin{gathered} A\text{ = 0.15}*0.3 \\ =0.045\text{ m}^2 \end{gathered}`

To find the time interval.

Step-by-step explanation:

The time interval can be calculated by the formula

`\Delta t=(NA\Delta B)/(\epsilon)`

On substituting the values, the time interval will be

`\begin{gathered} \Delta t\text{ = }(120*0.045*1.4)/(1.2) \\ =6.3\text{ s} \end{gathered}`

Final Answer: The time interval is 6.3 s