50,134 views
35 votes
35 votes
How much work is required to lift a 2.87 kg object from the bottom of a well 10.7 m deep? answer in:___J

User Xu Wang
by
2.7k points

1 Answer

10 votes
10 votes

We will determine the work as follows:

First, we recall that:


W=Fs

Then:


W=(2.87kg\ast9.8m/s^2)(10.7m)\Rightarrow W=300.9482J

So, the work will be 300.9482 Joules.