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What are the zeros of the function f(x) = x2 + 8x + 4, expressed in simplest radical form? x = –4 ± 2

2 Answers

1 vote

Answer:

a

Explanation:

User SGC
by
8.0k points
4 votes

Answer:


x=-4\pm 2√(3)

Explanation:

We have been given formula of a function
f(x)=x^2+8x+4. We are asked to find the zeros of our given function in simplest radical form.

We will use quadratic formula to solve our given problem.


x=(-b\pm√(b^2-4ac))/(2a)

Upon substituting our given values in above formula we will get,


x=(-8\pm√(8^2-4*1*4))/(2*1)


x=(-8\pm√(64-16))/(2)


x=(-8\pm√(48))/(2)


x=(-8)/(2)\pm(√(48))/(2)


x=-4\pm(√(16*3))/(2)


x=-4\pm(4√(3))/(2)


x=-4\pm 2√(3)

Therefore, solutions for our given equation are
x=-4\pm 2√(3).

User Horyun Lee
by
7.9k points

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