What are the zeros of the function f(x) = x2 + 8x + 4, expressed in simplest radical form? x = –4 ± 2

Question

asked Jun 17, 2017 34.2k views

2 Answers

Horyun Lee · Answer 1 · 2017-06-21T12:44:57+0000

Answer:

$x=-4\pm 2√(3)$

Explanation:

We have been given formula of a function
f(x)=x^2+8x+4 . We are asked to find the zeros of our given function in simplest radical form.

We will use quadratic formula to solve our given problem.

$x=(-b\pm√(b^2-4ac))/(2a)$

Upon substituting our given values in above formula we will get,

$x=(-8\pm√(8^2-4*1*4))/(2*1)$

$x=(-8\pm√(64-16))/(2)$

$x=(-8\pm√(48))/(2)$

$x=(-8)/(2)\pm(√(48))/(2)$

$x=-4\pm(√(16*3))/(2)$

$x=-4\pm(4√(3))/(2)$

$x=-4\pm 2√(3)$

Therefore, solutions for our given equation are
$x=-4\pm 2√(3)$ .