Question

The SI unit of time is the second, which is defined as 9,192,631,770 cycles of radiation associated with a certain emission process in the Cesium atom. Calculate the wavelength of this radiation (to 3 sig figs). In which region of the electromagnetic spectrum is the wavelength found?

Answer 1

Answer : The wavelength of this radiation is,
`3.26* 10^(-2)m` and in microwave region, the electromagnetic spectrum the wavelength is found.

Explanation : Given,

Frequency of radiation =
`9192631770s^(-1)`

Formula used :

`\\u=(c)/(\lambda)`

where,

`\\u` = frequency of radiation

`\lambda` = wavelength of radiation

c = speed of light =
`3* 10^8m/s`

Now put all the given values in the above formula, we get:

`9192631770s^(-1)=(3* 10^8m/s)/(\lambda)`

`\lambda=3.26* 10^(-2)m`

Thus, the wavelength of this radiation is,
`3.26* 10^(-2)m` and in microwave region, the electromagnetic spectrum the wavelength is found.