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Solid lithium iodide decomposes into solid lithium and iodine gas . Write a balanced chemical equation for this reaction.

User Bertrand P
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Final answer:

The balanced chemical equation for the decomposition of solid lithium iodide into solid lithium and iodine gas is 2 LiI(s) → 2 Li(s) + I2(g).

Step-by-step explanation:

The decomposition of solid lithium iodide (LiI) into solid lithium and iodine gas can be represented by a balanced chemical equation. In this reaction, the lithium iodide breaks down to form lithium metal and iodine gas, which can be represented as follows:

2 LiI(s) → 2 Li(s) + I2(g)

This equation is balanced because it has equal numbers of lithium and iodine atoms on both sides. It follows the law of conservation of mass, which states that matter is neither created nor destroyed in a chemical reaction.

User Jeffreyquan
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Balanced chemical equation is :
2LiCl(s) ----> 2Li(s) + Cl2(g)

User Samantha
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