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Please help me solve the following equation with respect to X:8ax–5(ax+b)=6b+3x with a≠1

User Zebrabox
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1 Answer

17 votes
17 votes

The given equation is

8ax–5(ax+b)=6b+3x

By expanding the parentheses, it becomes

8ax - 5ax - 5b = 6b + 3x

By collecting like terms, we have

8ax - 5ax - 3x = 6b + 5b

3ax - 3x = 11b

By factorizing the left side,

3x(a - 1) = 11b

Dividing both sides by 3(a - 1)

x = 11b/3(a - 1)

User Srking
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