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3 votes
What's the value of the product (3-2i)(3+2i)

User Afzal
by
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2 Answers

3 votes
We have to multiply given (3-2i)(3+2i)
(3-2i)(3+2i)=9-6i+6i+4i^2
9+4i^2
We know that i^2=-1, so lets substitute it
9+4*(-1)=9-4=5

User IHulk
by
8.1k points
5 votes

Answer:

the product (3-2i)(3+2i) is, 13

Explanation:

Using the identity rule:


(a+b)(a-b) = a^2-b^2

Given that:


(3-2i)(3+2i) ...[1]

here, i is the imaginary part.


i^2 = -1

Apply the rule on [1] we have;


(3)^2-(2i)^2


9-(4i^2)


9+4

Simplify:

13

Therefore, the product (3-2i)(3+2i) is, 13

User Angshuman Agarwal
by
8.0k points

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