Question

+Please help me i beg you i really need help please

Find the slope of the line that passes through the points (8, 7) and (11, 7).

Which is not a step used when constructing a perpendicular from a point not on a given line?

Without changing the compass, from each intersecting arc on the line, construct two arcs on the side opposite the given point.
Use your ruler and draw a straight line from the point through the line.
From the point not on the line stretch the compass and mark two arcs on the line.
Draw a line from the point to the intersecting arcs.

Answer 1

(8,7)(11,7)....when u have y values that r the same, it is a horizontal line. A horizontal line has a slope of 0.
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not 100% sure....but I think it may be B
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point F is (-2,3)
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P = a + b + c
a = (-8,-4), b = (-7,-8), c = (-6,-2)
distance from a to b = 4.12
distance from a to c = 2.83
distance from b to c = 6.08
P = 4.12 + 2.83 + 6.08 = 13.03 <==
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d = sqrt W^2 + L^2
d = sqrt 9^2 + 5^2
d = sqrt (81 + 25)
d = sqrt 106
d = 10.30 <==
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3x + 1 = 1/3x + 9...multiply by 3
9x + 3 = x + 27
9x - x = 27 - 3
8x = 24
x = 24/8
x = 3

AK = 3x + 1
AK = 3(3) + 1
AK = 9 + 1
AK = 10
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Line B has a slope of 2

Answer 2

I am so sorry no one responded right away!

1. To find the slope do the rise/sun. So you need to create a right triangle by connecting the points. If the line goes from left to right than it is a negative slope. But if it goes from right to left than it is a positive slope. Count how many down from the top point to the bottom and then count how many to connect the 2. But the points you give make a straight line. Meaning the slope is 0. Hope someone answer the rest of your questions because this is the only one I know!