Question

The male and female guests attending Patricia's party were surveyed to see if they drove to the party or did not drive. The data is displayed in the table below: Male Female Drove to the party 26 24 Did not drive to the party 34 116 If a guest is chosen at random from this group, what are the chances of choosing a guest who is male and did not drive to the party?

Answer 1

17%

Step-by-step explanation:

Step 1 :

34 is the amount of men who didnt drive to the party

200 is the total amount of people surveyed

use the formula P(event) =
`(outcomes )/(total )`

P(male and did not drive to the party) = 34/200=

17%

Answer 2

Gotcha covered.

The question asks for a random guest chosen randomly; so we know that there are a total of 200 guests. I got 200 by adding both male and female drivers and non-drivers.

Specifically, the question asks for male non-drivers. There are 34 male non-drivers out of 200 total guests.

Picking a male non-driver out of total guests results in this fraction: 34/200

We can simplify this fraction by dividing both sides by 2 since it can divide both numbers.

Once we do that, we get 17/100.

A percent is a number out of 100 and we know that number. It's 17, so we can say there's 17% a male non-driver would be picked out of the guests.

Hope this helped. If you have any questions, leave a comment. Good luck!