Question

1.The equation of line CD is (y−3) = − 2 (x − 4). What is the slope of a line perpendicular to line CD? 2.The equation of line AB is y = 2x + 4. Write an equation of a line parallel to line AB in slope-intercept form that contains point (3, −2). 3.The equation of line QR is y = negative 1/2x + 1. Write an equation of a line perpendicular to line QR in slope-intercept form that contains point (5, 6). 4.Line WX contains (−1, 2) and (4, 12) Line YZ contains points (5, 8) and (−2, −6). Lines WX and YZ are 5.Line CD contains points A (4, −7) and B (4, 8). The slope of line CD

Answer 1

m= y2-y1 ÷ X2 - X1

Explanation:

Answer 2

so here's how to do it,
slope intercept form is y=mx+b
m is the slope, b is the y- intercept, X is your unknown variable.

you need to solve to get y by its self to get your slope.

for perpendicular lines flip the slope

ex 1, smy=2x+6 --- slope of a perpendicular line will be 1/2

ex 2, y=3/2+8 ---8 perpendicular lien would have a slope of 2/3

parallel lines have the same slope so any equation with with the same slope will be parallel if it has the same degree.

ex. y=2x+14 is parallel to y= 2x+56

slope can be found using the following formula if you have two sets of points on the same line

m= y2-y1 ÷ X2 - X1