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Calculate the number of grams of nitrogen gas required to make 1.22 l of ammonia at stp
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Calculate the number of grams of nitrogen gas required to make 1.22 l of ammonia at stp

User Jamek
by
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1 Answer

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Molar mass N₂ = 28.0 g/mol

1 mole -------- 22.4 ( at STP)
? mole -------- 1.22 L

1.22 x 1 / 22.4 => 0.0544 moles

Therefore:

1 mole ------------- 28.0 g
0.0544 moles --- ??

0.0544 x 28.0 / 1 => 1.5232 g of N₂
User Kaleidic
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