Question

Solve this problem on paper using all four steps. Find four consecutive integers whose sum is 114.

Answer 1

a0=27

a1=28

a2=29

a3=30

Answer 2

Four consecutive integers whose sum is 114 are 27 , 28 , 29 , 30 .

Explanation:

Consecutive numbers are numbers having each number is one more than the previous number. like consecutive number of 2 is 3 .

We have to four consecutive integers whose sum is 114.

Let integers be in the form x , (x+1) , (x+2) , (x+3)

Given : Sum of integers be 114.

thus, x + (x+1) + (x+2) + (x+3) = 114

⇒ 4x +6 = 114

⇒ 4x = 114 -6

⇒ 4x = 108

⇒
`x= (108)/(4)`

⇒ x = 27

Thus, integers are,

x = 27

(x+1) = 27 + 1 = 28

(x+2) = 27 +2 = 29

(x+3) = 27 +3 = 30

Thus, four consecutive integers whose sum is 114 are 27 , 28 , 29 , 30 .