Question

What will be the c-value in the perfect square trinomial? x^2-x+c

Answer 1

A quadratic's general form is:

`ax^2+bx+c`

Our trinomial given is:

`x^2-x+c`

From matching it with the general form, we can say that:

`\begin{gathered} a=1 \\ b=-1 \end{gathered}`

For this to be a perfect square trinomial, c will take the value:

`c=((b)/(2))^2^{}`

We know b = -1, thus c will be:

`\begin{gathered} c=((b)/(2))^2 \\ c=(-(1)/(2))^2 \\ c=(1)/(4) \end{gathered}`

Thus, the value of c that will make this a perfect square trinomial:

`c=(1)/(4)`