Okay, here we have this:
We need to solve the following system of equations:
10x-6y=54
-4x+3y=-24
So, let's multiply the second equation by 2 to add the equations and cancel the y's:
10x-6y=54
-4x+3y=-24 (2)
------------------------
10x-6y=54
-8x+6y=-48 (2)
---------------------
2x=6
x=3
Now, let's replace x in the first equation to find the value of y:
10x-6y=54
10(3)-6y=54
30-6y=54
-6y=24
y=-4
Finally we obtain that x=3 and y=-4.