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2.)-2x + y = 3 -X + 4y = 12 GRAPHING

User Robotwasp
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1 Answer

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To graph this function, we follow the following steps:

Express the function in the Slope-Intercept form, y = ax + b. We make y the subject of the function

a. y = 2x + 3

when x = - 2

y = 2(-2) + 3 = - 4 + 3 = - 1

(x, y) = (-2, -1)

when x = 0

y = 2(0) + 3 = 0 + 3 = 3

(x, y) = (0, 3)

when x = 3

y = 2(3) + 3 = 6 + 3 = 9

(x, y) = (3, 9)

Slope = Δy / Δx = (9 - 3)/(3 - 0)

m = 6/3 = 2

The next step is to plot this values on a graph

b. -x + 4y = 12

Add x to both sides, we have:

4y = x + 12

Divide each element by 4, we have:

y = ¼x + 3

when x = -4

y = ¼(-4) + 3 = -1 + 3 = 2

(x, y) = (-4, 2)

when x = 0

y = ¼(0) + 3 = 0 + 3 = 3

(x, y) = (0, 3)

when x = 8

y = ¼(8) + 3 = 2 + 3 = 5

(x, y) = (8, 5)

Slope = Δy / Δx = (5 - 3)/(8 - 0)

m = 2/8 = 1/4

2.)-2x + y = 3 -X + 4y = 12 GRAPHING-example-1
User Dcolazin
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