68.8k views
0 votes
What is the molar concentration of phosphate ions in a 0.350 mli3po4 solution?

User Orejano
by
8.0k points

2 Answers

2 votes

Answer : The molar concentration of phosphate ions in lithium phosphate solution is, 0.350 M

Explanation : Given,

Concentration of lithium phosphate = 0.350 M

As lithium phosphate dissolve in water, it dissociates into lithium ions and phosphate ions.

The balanced reaction will be,


Li_3PO_4\rightarrow 3Li^++PO_4^(3-)

From the balanced reaction we conclude that,

As, mole ratio of
Li_3PO_4,
Li and
PO_4^(3-) is, 1 : 3 : 1

So,

The molar concentration of lithium ion = 3 × 0.350 M = 1.05 M

The molar concentration of phosphate ion = 0.350 M

Therefore, the molar concentration of phosphate ion is, 0.350 M

User Kal Zekdor
by
7.1k points
2 votes
When answering the above question or problem, first thing to realize is that the dissolution of the Na3PO4 can be written in a format that may be easier to see what is happening here.

Na3PO4 ----> 3 Na(+) + PO4(-3)

Now, you are starting out with a 0.35 M solution of Na3PO4, but when you dissolve the Na3PO4 into solution there are 3 Na(+) ions made for every Na3PO4 molecule that dissolves. Therefore to calculate the concentration of Na(+) ions in the final solution, take 3 times the inital concentration. 0.35 * 3 = 1.05 M in Na(+)
User Craig Hannon
by
7.7k points