Question

Graph the inequality on a plane.x+y≤3

Answer 1

Given: x+y≤3

`\begin{gathered} x+y-x\leq3-x \\ y\leq3-x \end{gathered}`

So, we have:

For x = 0,

`\begin{gathered} y\leq3-0 \\ \begin{equation*} y\leq3 \end{equation*} \end{gathered}`

For x = 3,

`\begin{gathered} y\leq3-3 \\ y\leq0 \end{gathered}`

And the coordinates are:

(0, 3) and (3,0)

Next, graphing: