Question

Followed by the previous question: presume that the electron performs a uniform circular motion around the hydrogen nucleus. What is the magnitude of the centripetal acceleration in m/sec2? (radius of the circle LaTeX: 5\times 10^{-11}5 × 10 − 11m; period of the motion LaTeX: 1.5 \times 10^{-16}1.5 × 10 − 16sec) Group of answer choices

Answer 1

`A_c=87.73*10^(21)m/s`

Step-by-step explanation:

From the question we are told that

`r=5* 10^(-11)`

`T=1.5 * 10^(-16)`

Generally the equation for velocity is mathematically given as

`Velocity (v)=(2 \pi r)/(t)`

`V=(2 \pi (5*10^(-11)))/(1.5*10^(-16))`

`V=(2 \pi (5*10^(-11)))/(1.5*10^(-16))`

Generally the equation for Centripetal acceleration is mathematically given as

`A_c=(V^2)/(r)`

`A_c=((20.944*10^5))/(r5*10^(-11))`

`A_c=87.73*10^(21)m/s`