Question

What is the factorization of 121b4-49

Answer 1

Since 121 is a perfect square, 12x12, and 49 is a perfect square, 7x7, and b^4 is a perfect square, b^2xb^2, you have what's called the difference of perfect squares. These factor into the sum and difference of the square roots. So (11b^2+7)(11b^2-7)

Answer 2

The factorization of the expression is
`121b^4-49=(11b-7)(11b+7)`

Explanation:

Given : Expression
`121b^4-49`

To find : What is the factorization of given expression?

Solution :

Expression
`121b^4-49`

Using algebraic identity,

`x^2-y^2=(x+y)(x-y)`

Making the term in square form,

`121b^4=(11b)^2`

`49=7^2`

So,
`121b^4-49=(11b)^2-7^2`

Applying property,

`121b^4-49=(11b-7)(11b+7)`

Therefore, The factorization of the expression is
`121b^4-49=(11b-7)(11b+7)`